[trao đổi] Chỉnh cách tính lịch arithmetic form thành astronomical form

dontsayloveme2

Thành viên kỳ cựu
Đọc đoạn sau thấy, hoàn toàn có thể cắt giảm nội dung [các phần làm tròn, lặp lại,…], tính chính xác NewMoonAA98 và SunLongitudeAA98,
sau đó tính chính xác < SunLongitudeAA98 of NewMoonAA98 [1] >
và < SunLongitudeAA98 ofNewMoonAA98 [2] >.
Nếu 2 số thực này có phần nguyên trước dấu “phẩy” đều bằng nhau, là 0 chẳng hạn – 2 sóc này nằm giữa Xuân Phân và Cốc Vũ – thì NewMoonAA98 [1] là điểm sóc tháng 2 NHUẬN [mão], NewMoonAA98 [2] là sóc tháng 3 [thìn].

Dưới đây là nguyên văn VietCalendar @author duc. Có những chỗ được chuyểnthành đậm vì đáng chú ý.
- Có đoạn SunLongitudeAA98 dùng để tính 1 thời điểm cụ thể nằm trong cung hoàng đạo nào
- KHÔNG CÓ đoạn nào dùng để tính điều ngược lại, các thời điểm trong 1 năm mà SunLongitude là số nguyên:
10 là điểm bắt đầu Đại Hàn > Vũ Thuỷ
11 là điểm bắt đầu Vũ Thuỷ > Xuân Phân
0 là điểm bắt đầu Xuân Phân > Cốc Vũ
... tương ứng với các cung hoàng đạo phương tây. Trong các bài sau, nếu có thể, sẽ có phần này [cơ sở để lập lá số TỬ BÌNH chính xác].
http://www.informatik.uni-leipzig.de/~duc/amlich/VietCalendar.java

/**
* @author duc
*
*/
public class VietCalendar {

public static final double PI = Math.PI;

/**
*
* @param dd
* @param mm
* @param yy
* @return the number of dayssince 1 January 4713 BC (Julian calendar)
*/
public static int jdFromDate(intdd, int mm, int yy) {
int a = (14 - mm) / 12;
int y = yy+4800-a;
int m = mm+12*a-3;
int jd = dd + (153*m+2)/5 +365*y + y/4 - y/100 + y/400 - 32045;
if (jd < 2299161) {
jd = dd + (153*m+2)/5 +365*y + y/4 - 32083;
}
//jd = jd - 1721425;
return jd;
}

/**
* http://www.tondering.dk/claus/calendar.html
* Section: Is there a formulafor calculating the Julian day number?
* @param jd - the number of dayssince 1 January 4713 BC (Julian calendar)
* @return
*/
public static int[] jdToDate(intjd) {
int a, b, c;
if (jd > 2299160) { //After 5/10/1582, Gregorian calendar
a = jd + 32044;
b = (4*a+3)/146097;
c = a - (b*146097)/4;
} else {
b = 0;
c = jd + 32082;
}
int d = (4*c+3)/1461;
int e = c - (1461*d)/4;
int m = (5*e+2)/153;
int day = e - (153*m+2)/5 +1;
int month = m + 3 -12*(m/10);
int year = b*100 + d - 4800 +m/10;
return new int[]{day, month,year};
}

/**
* Solar longitude in degrees
* Algorithm from: AstronomicalAlgorithms, by Jean Meeus, 1998
* @param jdn - number of dayssince noon UTC on 1 January 4713 BC
* @return
*/
public static doubleSunLongitude(double jdn) {
//returnCC2K.sunLongitude(jdn);
return SunLongitudeAA98(jdn);
}

public static double SunLongitudeAA98(double jdn) {
double T = (jdn - 2451545.0 )/ 36525; // Time in Julian centuries from 2000-01-01 12:00:00 GMT
double T2 = T*T;
double dr = PI/180; // degreeto radian
double M = 357.52910 +35999.05030*T - 0.0001559*T2 - 0.00000048*T*T2; // mean anomaly, degree
double L0 = 280.46645 +36000.76983*T + 0.0003032*T2; // mean longitude, degree
double DL = (1.914600 -0.004817*T - 0.000014*T2)*Math.sin(dr*M);
DL = DL + (0.019993 - 0.000101*T)*Math.sin(dr*2*M)+ 0.000290*Math.sin(dr*3*M);
double L = L0 + DL; // truelongitude, degree
L = L - 360*(INT(L/360)); // Normalizeto (0, 360)
return L;
}

public static double NewMoon(int k) {
//return CC2K.newMoonTime(k);
return NewMoonAA98(k);
}

/**
* Julian day number of the kthnew moon after (or before) the New Moon of 1900-01-01 13:51 GMT.
* Accuracy: 2 minutes
* Algorithm from: AstronomicalAlgorithms, by Jean Meeus, 1998
* @param k
* @return the Julian datenumber (number of days since noon UTC on 1 January 4713 BC) of the NewMoon
*/

public static doubleNewMoonAA98(int k) {
double T = k/1236.85; // Timein Julian centuries from 1900 January 0.5
double T2 = T * T;
double T3 = T2 * T;
double dr = PI/180;
double Jd1 = 2415020.75933 +29.53058868*k + 0.0001178*T2 - 0.000000155*T3;
Jd1 = Jd1 +0.00033*Math.sin((166.56 + 132.87*T - 0.009173*T2)*dr); // Mean new moon
double M = 359.2242 +29.10535608*k - 0.0000333*T2 - 0.00000347*T3; // Sun's mean anomaly
double Mpr = 306.0253 +385.81691806*k + 0.0107306*T2 + 0.00001236*T3; // Moon's mean anomaly
double F = 21.2964 +390.67050646*k - 0.0016528*T2 - 0.00000239*T3; // Moon's argument of latitude
double C1=(0.1734 -0.000393*T)*Math.sin(M*dr) + 0.0021*Math.sin(2*dr*M);
C1 = C1 -0.4068*Math.sin(Mpr*dr) + 0.0161*Math.sin(dr*2*Mpr);
C1 = C1 -0.0004*Math.sin(dr*3*Mpr);
C1 = C1 + 0.0104*Math.sin(dr*2*F) -0.0051*Math.sin(dr*(M+Mpr));
C1 = C1 -0.0074*Math.sin(dr*(M-Mpr)) + 0.0004*Math.sin(dr*(2*F+M));
C1 = C1 -0.0004*Math.sin(dr*(2*F-M)) - 0.0006*Math.sin(dr*(2*F+Mpr));
C1 = C1 + 0.0010*Math.sin(dr*(2*F-Mpr))+ 0.0005*Math.sin(dr*(2*Mpr+M));
double deltat;
if (T < -11) {
deltat= 0.001 +0.000839*T + 0.0002261*T2 - 0.00000845*T3 - 0.000000081*T*T3;
} else {
deltat= -0.000278 +0.000265*T + 0.000262*T2;
};
double JdNew = Jd1 + C1 -deltat;
return JdNew;
}

public static int INT(double d) {
return (int)Math.floor(d);
}

public static double getSunLongitude(int dayNumber, double timeZone) {
return SunLongitude(dayNumber- 0.5 - timeZone/24);
}

public static int getNewMoonDay(int k, double timeZone) {
double jd = NewMoon(k);
return INT(jd + 0.5+ timeZone/24);
}

public static int getLunarMonth11(int yy, double timeZone) {
double off = jdFromDate(31,12, yy) - 2415021.076998695;
int k = INT(off /29.530588853);
int nm = getNewMoonDay(k,timeZone);
int sunLong =INT(getSunLongitude(nm, timeZone)/30);
if (sunLong >= 9) {
nm = getNewMoonDay(k-1,timeZone);
}
return nm;
}

public static int getLeapMonthOffset(int a11, double timeZone) {
int k = INT(0.5 + (a11 -2415021.076998695) / 29.530588853);
int last; // Month 11contains point of sun longutide 3*PI/2 (December solstice)
int i = 1; // We start withthe month following lunar month 11
int arc =INT(getSunLongitude(getNewMoonDay(k+i, timeZone), timeZone)/30);
do {
last = arc;
i++;
arc = INT(getSunLongitude(getNewMoonDay(k+i,timeZone), timeZone)/30);
} while (arc != last&& i < 14);
return i-1;
}

/**
*
* @param dd
* @param mm
* @param yy
* @param timeZone
* @return array of [lunarDay,lunarMonth, lunarYear, leapOrNot]
*/
public static int[]convertSolar2Lunar(int dd, int mm, int yy, double timeZone) {
int lunarDay, lunarMonth,lunarYear, lunarLeap;
int dayNumber =jdFromDate(dd, mm, yy);
int k = INT((dayNumber - 2415021.076998695)/ 29.530588853);
int monthStart =getNewMoonDay(k+1, timeZone);
if (monthStart >dayNumber) {
monthStart =getNewMoonDay(k, timeZone);
}
int a11 = getLunarMonth11(yy,timeZone);
int b11 = a11;
if (a11 >= monthStart) {
lunarYear = yy;
a11 =getLunarMonth11(yy-1, timeZone);
} else {
lunarYear = yy+1;
b11 =getLunarMonth11(yy+1, timeZone);
}
lunarDay = dayNumber-monthStart+1;
int diff = INT((monthStart -a11)/29);
lunarLeap = 0;
lunarMonth = diff+11;
if (b11 - a11 > 365) {
int leapMonthDiff =getLeapMonthOffset(a11, timeZone);
if (diff >=leapMonthDiff) {
lunarMonth = diff + 10;
if (diff ==leapMonthDiff) {
lunarLeap = 1;
}
}
}
if (lunarMonth > 12) {
lunarMonth = lunarMonth -12;
}
if (lunarMonth >= 11&& diff < 4) {
lunarYear -= 1;
}
return new int[]{lunarDay,lunarMonth, lunarYear, lunarLeap};
}

public static int[] convertLunar2Solar(int lunarDay, int lunarMonth, intlunarYear, int lunarLeap, double timeZone) {
int a11, b11;
if (lunarMonth < 11) {
a11 =getLunarMonth11(lunarYear-1, timeZone);
b11 =getLunarMonth11(lunarYear, timeZone);
} else {
a11 =getLunarMonth11(lunarYear, timeZone);
b11 = getLunarMonth11(lunarYear+1,timeZone);
}
int k = INT(0.5 + (a11 -2415021.076998695) / 29.530588853);
int off = lunarMonth - 11;
if (off < 0) {
off += 12;
}
if (b11 - a11 > 365) {
int leapOff = getLeapMonthOffset(a11,timeZone);
int leapMonth = leapOff -2;
if (leapMonth < 0) {
leapMonth += 12;
}
if (lunarLeap != 0&& lunarMonth != leapMonth) {
System.out.println("Invalid input!");
return new int[]{0,0, 0};
} else if (lunarLeap != 0|| off >= leapOff) {
off += 1;
}
}
int monthStart =getNewMoonDay(k+off, timeZone);
returnjdToDate(monthStart+lunarDay-1);
}

public static void main(String[] args) {
doubleTZ = 7.0;
intstart = jdFromDate(1, 1, 2001);
intstep = 15;
intcount = -1;
while(count++ < 240) {
intjd = start + step*count;
int[]s = jdToDate(jd);
int[]l = convertSolar2Lunar(s[0], s[1], s[2], TZ);
int[]s2 = convertLunar2Solar(l[0], l[1], l[2], l[3], TZ);
if(s[0] == s2[0] && s[1] == s2[1] && s[2] == s2[2]) {
System.out.println("OK!"+s[0]+"/"+s[1]+"/"+s[2]+" ->"+l[0]+"/"+l[1]+"/"+l[2]+(l[3] == 0 ? "" :" leap"));
}else {
System.err.println("ERROR!"+s[0]+"/"+s[1]+"/"+s[2]+" ->"+l[0]+"/"+l[1]+"/"+l[2]+(l[3] == 0 ? "" :" leap"));
}
}
}
}
 

dontsayloveme2

Thành viên kỳ cựu
http://www.informatik.uni-leipzig.de/~duc/amlich/amlich-aa98.js

/*
* Copyright (c) 2006 Ho Ngoc Duc. All Rights Reserved.
* Astronomical algorithms from the book "Astronomical Algorithms" by Jean Meeus, 1998
*/
var PI = Math.PI;

/* Discard the fractional part of a number, e.g., INT(3.2) = 3 */
function INT(d) {
return Math.floor(d);
}

/* Compute the (integral) Julian day number of day dd/mm/yyyy, i.e., the number
* of days between 1/1/4713 BC (Julian calendar) and dd/mm/yyyy.
*/
function jdFromDate(dd, mm, yy) {
var a, y, m, jd;
a = INT((14 - mm) / 12);
y = yy+4800-a;
m = mm+12*a-3;
jd = dd + INT((153*m+2)/5) + 365*y + INT(y/4) - INT(y/100) + INT(y/400) - 32045;
if (jd < 2299161) {
jd = dd + INT((153*m+2)/5) + 365*y + INT(y/4) - 32083;
}
return jd;
}

/* Convert a Julian day number to day/month/year. Parameter jd is an integer */
function jdToDate(jd) {
var a, b, c, d, e, m, day, month, year;
if (jd > 2299160) { // After 5/10/1582, Gregorian calendar
a = jd + 32044;
b = INT((4*a+3)/146097);
c = a - INT((b*146097)/4);
} else {
b = 0;
c = jd + 32082;
}
d = INT((4*c+3)/1461);
e = c - INT((1461*d)/4);
m = INT((5*e+2)/153);
day = e - INT((153*m+2)/5) + 1;
month = m + 3 - 12*INT(m/10);
year = b*100 + d - 4800 + INT(m/10);
return new Array(day, month, year);
}

/* Compute the time of the k-th new moon after the new moon of 1/1/1900 13:52 UCT
* (measured as the number of days since 1/1/4713 BC noon UCT, e.g., 2451545.125 is 1/1/2000 15:00 UTC).
* Returns a floating number, e.g., 2415079.9758617813 for k=2 or 2414961.935157746 for k=-2
*/
function NewMoon(k) {
var T, T2, T3, dr, Jd1, M, Mpr, F, C1, deltat, JdNew;
T = k/1236.85; // Time in Julian centuries from 1900 January 0.5
T2 = T * T;
T3 = T2 * T;
dr = PI/180;
Jd1 = 2415020.75933 + 29.53058868*k + 0.0001178*T2 - 0.000000155*T3;
Jd1 = Jd1 + 0.00033*Math.sin((166.56 + 132.87*T - 0.009173*T2)*dr); // Mean new moon
M = 359.2242 + 29.10535608*k - 0.0000333*T2 - 0.00000347*T3; // Sun's mean anomaly
Mpr = 306.0253 + 385.81691806*k + 0.0107306*T2 + 0.00001236*T3; // Moon's mean anomaly
F = 21.2964 + 390.67050646*k - 0.0016528*T2 - 0.00000239*T3; // Moon's argument of latitude
C1=(0.1734 - 0.000393*T)*Math.sin(M*dr) + 0.0021*Math.sin(2*dr*M);
C1 = C1 - 0.4068*Math.sin(Mpr*dr) + 0.0161*Math.sin(dr*2*Mpr);
C1 = C1 - 0.0004*Math.sin(dr*3*Mpr);
C1 = C1 + 0.0104*Math.sin(dr*2*F) - 0.0051*Math.sin(dr*(M+Mpr));
C1 = C1 - 0.0074*Math.sin(dr*(M-Mpr)) + 0.0004*Math.sin(dr*(2*F+M));
C1 = C1 - 0.0004*Math.sin(dr*(2*F-M)) - 0.0006*Math.sin(dr*(2*F+Mpr));
C1 = C1 + 0.0010*Math.sin(dr*(2*F-Mpr)) + 0.0005*Math.sin(dr*(2*Mpr+M));
if (T < -11) {
deltat= 0.001 + 0.000839*T + 0.0002261*T2 - 0.00000845*T3 - 0.000000081*T*T3;
} else {
deltat= -0.000278 + 0.000265*T + 0.000262*T2;
};
JdNew = Jd1 + C1 - deltat;
return JdNew;
}

/* Compute the longitude of the sun at any time.
* Parameter: floating number jdn, the number of days since 1/1/4713 BC noon
*/
function SunLongitude(jdn) {
var T, T2, dr, M, L0, DL, L;
T = (jdn - 2451545.0 ) / 36525; // Time in Julian centuries from 2000-01-01 12:00:00 GMT
T2 = T*T;
dr = PI/180; // degree to radian
M = 357.52910 + 35999.05030*T - 0.0001559*T2 - 0.00000048*T*T2; // mean anomaly, degree
L0 = 280.46645 + 36000.76983*T + 0.0003032*T2; // mean longitude, degree
DL = (1.914600 - 0.004817*T - 0.000014*T2)*Math.sin(dr*M);
DL = DL + (0.019993 - 0.000101*T)*Math.sin(dr*2*M) + 0.000290*Math.sin(dr*3*M);
L = L0 + DL; // true longitude, degree
L = L*dr;
L = L - PI*2*(INT(L/(PI*2))); // Normalize to (0, 2*PI)
return L;
}

/* Compute sun position at midnight of the day with the given Julian day number.
* The time zone if the time difference between local time and UTC: 7.0 for UTC+7:00.
* The function returns a number between 0 and 11.
* From the day after March equinox and the 1st major term after March equinox, 0 is returned.
* After that, return 1, 2, 3 ...
*/
function getSunLongitude(dayNumber, timeZone) {
return INT(SunLongitude(dayNumber - 0.5 - timeZone/24)/PI*6);
}
/* giải thích vì sao chia cho PI*6
* 0*PI/6, 1*PI/6, 2*PI/6, 3*PI/6, 4*PI/6, 5*PI/6, 6*PI/6, 7*PI/6, 8*PI/6, 9*PI/6, 10*PI/6, 11*PI/6.
* Các điểm "Phân-Chí" được định nghĩa bằng các tọa độ sau
* Xuân phân: 0, Hạ chí: PI/2, Thu phân: PI, Đông chí: 3*PI/2.
*/

/* Compute the day of the k-th new moon in the given time zone.
* The time zone if the time difference between local time and UTC: 7.0 for UTC+7:00
*/
function getNewMoonDay(k, timeZone) {
return INT(NewMoon(k) + 0.5 + timeZone/24);
}

/* Find the day that starts the luner month 11 of the given year for the given time zone */
function getLunarMonth11(yy, timeZone) {
var k, off, nm, sunLong;
//off = jdFromDate(31, 12, yy) - 2415021.076998695;
off = jdFromDate(31, 12, yy) - 2415021;
k = INT(off / 29.530588853);
nm = getNewMoonDay(k, timeZone);
sunLong = getSunLongitude(nm, timeZone); // sun longitude at local midnight
if (sunLong >= 9) {
nm = getNewMoonDay(k-1, timeZone);
}
return nm;
}

/* Find the index of the leap month after the month starting on the day a11. */
function getLeapMonthOffset(a11, timeZone) {
var k, last, arc, i;
k = INT((a11 - 2415021.076998695) / 29.530588853 + 0.5);
last = 0;
i = 1; // We start with the month following lunar month 11
arc = getSunLongitude(getNewMoonDay(k+i, timeZone), timeZone);
do {
last = arc;
i++;
arc = getSunLongitude(getNewMoonDay(k+i, timeZone), timeZone);
} while (arc != last && i < 14);
return i-1;
}

/* Comvert solar date dd/mm/yyyy to the corresponding lunar date */
function convertSolar2Lunar(dd, mm, yy, timeZone) {
var k, dayNumber, monthStart, a11, b11, lunarDay, lunarMonth, lunarYear, lunarLeap;
dayNumber = jdFromDate(dd, mm, yy);
k = INT((dayNumber - 2415021.076998695) / 29.530588853);
monthStart = getNewMoonDay(k+1, timeZone);
if (monthStart > dayNumber) {
monthStart = getNewMoonDay(k, timeZone);
}
//alert(dayNumber+" -> "+monthStart);
a11 = getLunarMonth11(yy, timeZone);
b11 = a11;
if (a11 >= monthStart) {
lunarYear = yy;
a11 = getLunarMonth11(yy-1, timeZone);
} else {
lunarYear = yy+1;
b11 = getLunarMonth11(yy+1, timeZone);
}
lunarDay = dayNumber-monthStart+1;
diff = INT((monthStart - a11)/29);
lunarLeap = 0;
lunarMonth = diff+11;
if (b11 - a11 > 365) {
leapMonthDiff = getLeapMonthOffset(a11, timeZone);
if (diff >= leapMonthDiff) {
lunarMonth = diff + 10;
if (diff == leapMonthDiff) {
lunarLeap = 1;
}
}
}
if (lunarMonth > 12) {
lunarMonth = lunarMonth - 12;
}
if (lunarMonth >= 11 && diff < 4) {
lunarYear -= 1;
}
return new Array(lunarDay, lunarMonth, lunarYear, lunarLeap);
}

/* Convert a lunar date to the corresponding solar date
* Đáng chú ý
*/
function convertLunar2Solar(lunarDay, lunarMonth, lunarYear, lunarLeap, timeZone) {
var k, a11, b11, off, leapOff, leapMonth, monthStart;
if (lunarMonth < 11) {
a11 = getLunarMonth11(lunarYear-1, timeZone);
b11 = getLunarMonth11(lunarYear, timeZone);
} else {
a11 = getLunarMonth11(lunarYear, timeZone);
b11 = getLunarMonth11(lunarYear+1, timeZone);
}
k = INT(0.5 + (a11 - 2415021.076998695) / 29.530588853);
off = lunarMonth - 11;
if (off < 0) {
off += 12;
}
if (b11 - a11 > 365) {
leapOff = getLeapMonthOffset(a11, timeZone);
leapMonth = leapOff - 2;
if (leapMonth < 0) {
leapMonth += 12;
}
if (lunarLeap != 0 && lunarMonth != leapMonth) {
return new Array(0, 0, 0);
} else if (lunarLeap != 0 || off >= leapOff) {
off += 1;
}
}
monthStart = getNewMoonDay(k+off, timeZone);
return jdToDate(monthStart+lunarDay-1);
}
 
Top